Quadratic Equations
A quadratic equation is of the form ax² + bx + c = 0 where a ≠ 0. Every quadratic equation has exactly two roots (real or complex), and those roots reveal key properties of the equation.
Fundamental Principles
Quadratic Equation
An equation of degree 2 written as ax² + bx + c = 0, where a, b, c are constants and a ≠ 0.
Discriminant
The value D = b² - 4ac. If D > 0: two distinct real roots. If D = 0: two equal real roots. If D < 0: no real roots (complex roots).
Vieta's Formulas
For ax² + bx + c = 0 with roots α and β: Sum of roots α + β = -b/a. Product of roots αβ = c/a.
Essential Formulation Tips
- Try factoring first — it's the fastest method when it works.
- Use the quadratic formula when factoring is not obvious.
- Always check the discriminant to know what kind of roots to expect.
- Vieta's formulas let you find sum and product of roots without solving.
Shortcut Execution Techniques
- Sum of roots = -b/a; Product of roots = c/a.
- If roots are equal and opposite → b = 0.
- If product of roots is negative → roots have opposite signs.
- If sum of roots is 0 → roots are equal and opposite.
Contextual Inquiries (FAQs)
Q: What is the quadratic formula?
A: x = (-b ± √(b² - 4ac)) / 2a.
Q: What does it mean if D = 0?
A: The quadratic has two equal (repeated) roots: x = -b/2a.
Q: Can a quadratic equation have more than 2 roots?
A: No. A quadratic equation always has exactly 2 roots (counting multiplicity).
Example Breakdown: Solving by Factoring
Factoring is the quickest method for simple quadratics.Find two numbers that multiply to 6 and add to -5: -2 and -3
(x - 2)(x - 3) = 0
x = 2 or x = 3
Example Breakdown: Using the Quadratic Formula
Always simplify the equation before applying the formula.a = 2, b = -4, c = -6
D = (-4)² - 4(2)(-6) = 16 + 48 = 64
x = (4 ± 8) / 4
x = 3 or x = -1
Example Breakdown: Using Vieta's Formulas
Vieta's formulas save time in MCQ exams.Sum of roots = -b/a = 7/3
Product of roots = c/a = 2/3
Quadratic Equations Practice Set 1
Basic: solving quadratics by factoring.
Q1. Solve: x² - 7x + 12 = 0.
Q2. Which of the following is a root of x² - 9 = 0?
Q3. Solve: x² + 5x + 6 = 0.
Q4. Find the roots of x² - x - 6 = 0.
Q5. Solve: 2x² - 8 = 0.
Q6. Which value satisfies x² - 4x = 0?
Q7. Solve: x² + 2x - 8 = 0.
Q8. What are the roots of 3x² - 12x = 0?
Q9. Solve: (x-5)(x+2) = 0.
Q10. Solve: x² - 16 = 0.